Math Problem Solver

\[ 1\frac{4}{11} + 1\frac{5}{11} + 1\frac{6}{11} = \frac{48}{11} = 4.\overline{36} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{1}\), \(\frac{4}{11}\), \(\frac{1}{1}\), \(\frac{5}{11}\), \(\frac{1}{1}\), and \(\frac{6}{11}\) is \(11\). \[ \begin{aligned} 1\frac{4}{11} + 1\frac{5}{11} + 1\frac{6}{11} &= \frac{1 \cdot 11}{1 \cdot 11} + \frac{4 \cdot 1}{11 \cdot 1} + \frac{1 \cdot 11}{1 \cdot 11} + \frac{5 \cdot 1}{11 \cdot 1} + \frac{1 \cdot 11}{1 \cdot 11} + \frac{6 \cdot 1}{11 \cdot 1} \\ &= \frac{11 + 4 + 11 + 5 + 11 + 6}{11} \\ &= \frac{48}{11} \end{aligned} \]