(-6/0.05+-3/0.2)-(4-0.3/-0.2)

asked by guest
on Sep 23, 2024 at 5:15 am



You asked:

Evaluate the expression: \(\frac{-6}{0.05} + \frac{-3}{0.2} - \left(4 - \frac{0.3}{-0.2}\right)\)

MathBot Answer:

\[\frac{-6}{0.05} + \frac{-3}{0.2} - \left(4 - \frac{0.3}{-0.2}\right) = - \frac{281}{2} = -140.5\]

\[\begin{aligned}\frac{-6}{0.05} + \frac{-3}{0.2} - \left(4 - \frac{0.3}{-0.2}\right)& = -6 \cdot \frac{1}{\frac{5}{100}} - 3 \cdot \frac{1}{\frac{2}{10}} - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{2}{10}}\right)\\& = -6 \cdot \frac{1}{\frac{1}{20}} - 3 \cdot \frac{1}{\frac{2}{10}} - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{2}{10}}\right)\\& = -120 - 3 \cdot \frac{1}{\frac{2}{10}} - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{2}{10}}\right)\\& = -120 - 3 \cdot \frac{1}{\frac{1}{5}} - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{2}{10}}\right)\\& = -120 - 15 - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{2}{10}}\right)\\& = -120 - 15 - \left(4 - \frac{3}{10} \cdot \frac{1}{\frac{-1}{5}}\right)\\& = -120 - 15 - \left(4 - \frac{3}{10} \cdot \frac{1}{- \frac{1}{5}}\right)\\& = -120 - 15 - \left(4 - \frac{-3}{2}\right)\\& = -120 - 15 - \left(4 - - \frac{3}{2}\right)\\& = -120 - 15 - \left(4 + \frac{3}{2}\right)\\& = -120 - 15 - \frac{11}{2}\\& = -135 - \frac{11}{2}\\& = - \frac{281}{2}\end{aligned}\]

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