𝑒^(2𝑥) − 𝑒𝑥 = 20

asked by guest
on Nov 21, 2024 at 2:12 am



You asked:

Investigate the equation: e2x−ex=20{e}^{2 x} - e x = 20.

MathBot Answer:

The 2 solutions to the equation are: x=0.000000149618465337784208021928294178188989327951311308−20e≈−7.3575887x=8.95361765221300383459173948559510882112098944712−20e≈1.5960288\begin{aligned}x &= 0.000000149618465337784208021928294178188989327951311308 - \frac{20}{e} \approx -7.3575887\\x &= 8.95361765221300383459173948559510882112098944712 - \frac{20}{e} \approx 1.5960288\end{aligned}

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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