-3tant - 2tan2t / 3cott - 2tan2t

asked by guest
on Jan 31, 2025 at 9:20 pm



You asked:

Evaluate the expression: −(3tan⁡(t))−2tan⁡(2t)3cot⁡(t)−2tan⁡(2t)-\left( 3 \tan\left( t \right) \right) - \frac{2 \tan\left( 2 t \right)}{3 \cot\left( t \right)} - 2 \tan\left( 2 t \right)

MathBot Answer:

Evaluated



−(3tan⁡(t))−2tan⁡(2t)3cot⁡(t)−2tan⁡(2t)=−2tan⁡(2t)−2tan⁡(2t)3cot⁡(t)−3tan⁡(t)\displaystyle -\left( 3 \tan\left( t \right) \right) - \frac{2 \tan\left( 2 t \right)}{3 \cot\left( t \right)} - 2 \tan\left( 2 t \right) = - 2 \tan{\left(2 t \right)} - \frac{2 \tan{\left(2 t \right)}}{3 \cot{\left(t \right)}} - 3 \tan{\left(t \right)}

Factored

−(3tan⁡(t))−2tan⁡(2t)3cot⁡(t)−2tan⁡(2t)=−6tan⁡(2t)cot⁡(t)+2tan⁡(2t)+9tan⁡(t)cot⁡(t)3cot⁡(t)-\left( 3 \tan\left( t \right) \right) - \frac{2 \tan\left( 2 t \right)}{3 \cot\left( t \right)} - 2 \tan\left( 2 t \right) = - \frac{6 \tan{\left(2 t \right)} \cot{\left(t \right)} + 2 \tan{\left(2 t \right)} + 9 \tan{\left(t \right)} \cot{\left(t \right)}}{3 \cot{\left(t \right)}}

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