(1 + y ^ 2 + 3x ^ 2 * y) * dx + (- 1 + 2xy + x ^ 3) * dy = 0

asked by guest
on Mar 25, 2025 at 7:55 am



You asked:

Investigate the equation: (1+y2+3x2y)⋅dx+(−1+2xy+x3)⋅dy=0\left(1 + {y}^{2} + 3 {x}^{2} y\right) \cdot d x + \left(-1 + 2 x y + {x}^{3}\right) \cdot d y = 0.

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