\frac{x\ -2}{4}\ge \frac{9}{x\ +\ 3}
You asked:
Solve the inequality \( \frac{x - 2}{4} \ge \frac{9}{x + 3} \) for the variable \(x\).
MathBot Answer:
\(-7 \le x < -3\) or \(6 \le x < \infty\)
\frac{x\ -2}{4}\ge \frac{9}{x\ +\ 3}
You asked:
MathBot Answer:
\(-7 \le x < -3\) or \(6 \le x < \infty\)