6(x+1)+4(2x-1)>4(x+2)+ $\sqrt{16}$

asked by guest
on Nov 10, 2024 at 2:51 pm



You asked:

Solve the inequality \( 6 \cdot \left(x + 1\right) + 4 \cdot \left(2 x - 1\right) > 4 \cdot \left(x + 2\right) + \sqrt{16} \) for the variable \(x\).

MathBot Answer:

\[x > 1\]

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