Math Problem Solver

$$32 - 9=23$$

$$\begin{aligned} \overset{\mathtt{{\scriptscriptstyle 2}}}{\cancel{\mathtt{3}}}\overset{\mathtt{{\scriptscriptstyle 12}}}{\cancel{\mathtt{2}}}\\ \mathtt{-\phantom{0}}\phantom{0}\mathtt{9}\\ \hline \mathtt{2}\mathtt{3} \end{aligned}$$

Borrow $10^{1}$, resulting in $2$ in the $10^{1}$ place, and $12$ in the $10^{0}$ place.

$3$ is the digit in the $10^{0}$ place. $12 \times 10^{0} - 9 \times 10^{0} = 3 \times 10^{0}$.

$2$ is the digit in the $10^{1}$ place. $2 \times 10^{1} - 0 \times 10^{1} = 2 \times 10^{1}$.