$\frac{a-3\}{6\}$ - $\frac{2a+1\}{3\}$ + $\frac{4-a\}{2\}$
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$\frac{a-3\}{6\}$ - $\frac{2a+1\}{3\}$ + $\frac{4-a\}{2\}$
MathBot Answer:
MathBot is working on a solution to your problem.