(x+2021)/4+(x+5)/2020=(x+2019)/6+(x+7)/2018

asked by guest
on Mar 30, 2025 at 8:16 am



You asked:

Solve the equation x+20214+x+52020=x+20196+x+72018\frac{x + 2021}{4} + \frac{x + 5}{2020} = \frac{x + 2019}{6} + \frac{x + 7}{2018} for the variable xx.

MathBot Answer:

The solution is: x=−2025x = -2025

253x1010+102061202=506x3027+3395321009254771x3057270=−34394085203818x=−2025\begin{aligned}\frac{253 x}{1010} + \frac{102061}{202} &= \frac{506 x}{3027} + \frac{339532}{1009}\\\frac{254771 x}{3057270} &= - \frac{34394085}{203818}\\x &= -2025\end{aligned}

+ Submit Question