f'(X) = (1/x + 1/x^2) (3x^2 + 27)
You asked:
Investigate the equation: \(f'\left( X \right) = \left(\frac{1}{x} + \frac{1}{{x}^{2}}\right) \cdot \left(3 \cdot {x}^{2} + 27\right)\).
MathBot Answer:
\[f{\left(X \right)} = 3 X + 3 X x + \frac{27 X}{x} + \frac{27 X}{x^{2}} + C_{1}\]
\(C_{1}\) is an arbitrary constant.