(2*a*b^(3/2)) (1/27*a^(-3/2)b^(-6/2))

asked by guest
on Jan 19, 2025 at 3:04 pm



You asked:

Evaluate the expression: 2ab32⋅127a−32b−622 a {b}^{\frac{3}{2}} \cdot \frac{1}{27} {a}^{\frac{-3}{2}} {b}^{\frac{-6}{2}}

MathBot Answer:

2ab32⋅127a−32b−62=227ab322 a {b}^{\frac{3}{2}} \cdot \frac{1}{27} {a}^{\frac{-3}{2}} {b}^{\frac{-6}{2}} = \frac{2}{27 \sqrt{a} b^{\frac{3}{2}}}

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