Solve the equation sin(x)2+2sin(x)−3=0 for the variable x.
MathBot Answer:
The principal value in −2π≤x≤2π is x≈1.5707963
The real solutions are: {2π(4n+1)n∈Z}
The complex solutions are: xx={23π−ilog(3+22)+2πnn∈Z}≈{6.2831853n+4.712389−1.7627472i∣n∈Z}={23π−ilog(3−22)+2πnn∈Z}≈{6.2831853n+4.712389+1.7627472i∣n∈Z}