(x-a³)/(b²-bc+c²) +(x-b³)/(c²-ca+a²)+(x-c³)/(a²-ab+b²)=2(a+b+c)
You asked:
Investigate the equation: \(\frac{x - {a}^{3}}{{b}^{2} - b c + {c}^{2}} + \frac{x - {b}^{3}}{{c}^{2} - c a + {a}^{2}} + \frac{x - {c}^{3}}{{a}^{2} - a b + {b}^{2}} = 2 \cdot \left(a + b + c\right)\).