Math Problem Solver

\[ 67.45 + 79.76 + 52.40 + 114.95 + 169.80 + 110.85 + 79.76 + 55.56 + 49.95 = \frac{19512}{25} = 780.48 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{67}{1}\), \(\frac{45}{100}\), \(\frac{79}{1}\), \(\frac{76}{100}\), \(\frac{52}{1}\), \(\frac{4}{10}\), \(\frac{114}{1}\), \(\frac{95}{100}\), \(\frac{169}{1}\), \(\frac{8}{10}\), \(\frac{110}{1}\), \(\frac{85}{100}\), \(\frac{79}{1}\), \(\frac{76}{100}\), \(\frac{55}{1}\), \(\frac{56}{100}\), \(\frac{49}{1}\), and \(\frac{95}{100}\) is \(100\). \[ \begin{aligned} 67.45 + 79.76 + 52.40 + 114.95 + 169.80 + 110.85 + 79.76 + 55.56 + 49.95 &= \frac{67 \cdot 100}{1 \cdot 100} + \frac{45 \cdot 1}{100 \cdot 1} + \frac{79 \cdot 100}{1 \cdot 100} + \frac{76 \cdot 1}{100 \cdot 1} + \frac{52 \cdot 100}{1 \cdot 100} + \frac{4 \cdot 10}{10 \cdot 10} + \frac{114 \cdot 100}{1 \cdot 100} + \frac{95 \cdot 1}{100 \cdot 1} + \frac{169 \cdot 100}{1 \cdot 100} + \frac{8 \cdot 10}{10 \cdot 10} + \frac{110 \cdot 100}{1 \cdot 100} + \frac{85 \cdot 1}{100 \cdot 1} + \frac{79 \cdot 100}{1 \cdot 100} + \frac{76 \cdot 1}{100 \cdot 1} + \frac{55 \cdot 100}{1 \cdot 100} + \frac{56 \cdot 1}{100 \cdot 1} + \frac{49 \cdot 100}{1 \cdot 100} + \frac{95 \cdot 1}{100 \cdot 1} \\ &= \frac{6700 + 45 + 7900 + 76 + 5200 + 40 + 11400 + 95 + 16900 + 80 + 11000 + 85 + 7900 + 76 + 5500 + 56 + 4900 + 95}{100} \\ &= \frac{78048}{100} \\&= \frac{19512}{25} \end{aligned} \]