Power[e,x] - ln(Power[cos,2]) + ln(1+Power[tan,2])
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Power[e,x] - ln(Power[cos,2]) + ln(1+Power[tan,2])
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.