\log _{\frac{1}{2}}\left(2x+8\right)=0
You asked:
Solve the equation \(\log_{\frac{1}{2}}\left( 2 x + 8 \right) = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{7}{2} = -3.5\]
\log _{\frac{1}{2}}\left(2x+8\right)=0
You asked:
MathBot Answer:
The solution is: \[x = - \frac{7}{2} = -3.5\]