2y^3 -9y^2 -28y-15

asked by guest
on Nov 25, 2024 at 11:14 am



You asked:

Evaluate the expression: \(2 {y}^{3} - 9 {y}^{2} - 28 y - 15\)

MathBot Answer:

Evaluated



\(\displaystyle 2 {y}^{3} - 9 {y}^{2} - 28 y - 15 = 2 y^{3} - 9 y^{2} - 28 y - 15 \)

Factored

\[2 {y}^{3} - 9 {y}^{2} - 28 y - 15 = \left(2 y + 3\right) \left(y^{2} - 6 y - 5\right)\]

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