The triangular surface lies in the plane passing through
𝐴
(
1
,
0
,
0
)
A(1,0,0),
𝐵
(
0
,
2
,
0
)
B(0,2,0), and
𝐶
(
0
,
0
,
1
)
C(0,0,1). The equation of the plane can be determined using these points:
Plane:
𝑥
+
𝑦
2
+
𝑧
=
1
Plane: x+
2
y
+z=1
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