DL ln(1+x)

asked by guest
on Sep 20, 2024 at 12:20 pm



You asked:

Evaluate the expression: \(D L \cdot \ln\left( 1 + x \right)\)

MathBot Answer:

\[D L \cdot \ln\left( 1 + x \right) = D L \log{\left(x + 1 \right)}\]

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