Math Problem Solver

$$1368 + 1257=2625$$

$$\begin{aligned} \mathtt{1}\overset{\mathtt{1}}{\mathtt{3}}\overset{\mathtt{1}}{\mathtt{6}}\mathtt{8}\\ \mathtt{+\phantom{0}}\mathtt{1}\mathtt{2}\mathtt{5}\mathtt{7}\\ \hline \mathtt{2}\mathtt{6}\mathtt{2}\mathtt{5} \end{aligned}$$

$5$ is the digit in the $10^{0}$ place. $8 \times 10^{0} + 7 \times 10^{0} = 15 \times 10^{0} = 1 \times 10^{1} + 5 \times 10^{0}$.$1 \times 10^{1}$ carries to the $10^{1}$ place.

$2$ is the digit in the $10^{1}$ place. $1 \times 10^{1} + 6 \times 10^{1} + 5 \times 10^{1} = 12 \times 10^{1} = 1 \times 10^{2} + 2 \times 10^{1}$.$1 \times 10^{2}$ carries to the $10^{2}$ place.

$6$ is the digit in the $10^{2}$ place. $1 \times 10^{2} + 3 \times 10^{2} + 2 \times 10^{2} = 6 \times 10^{2}$.

$2$ is the digit in the $10^{3}$ place. $1 \times 10^{3} + 1 \times 10^{3} = 2 \times 10^{3}$.