(n-1)³+3(n-1)²+2(n-1)=0
You asked:
Solve the equation \({\left( n - 1 \right)}^{3} + 3 \cdot {\left( n - 1 \right)}^{2} + 2 \cdot \left(n - 1\right) = 0\) for the variable \(n\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}n &= -1\\n &= 0\\n &= 1\end{aligned}\]