15a2\sqrt{15a^2}15a2 5a5\sqrt{5a^5}5a5
asked by guest on Nov 17, 2024 at 9:31 am
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MathBot Answer:
15a2⋅5a5=53a2a5\sqrt{15 {a}^{2}} \cdot \sqrt{5 {a}^{5}} = 5 \sqrt{3} \sqrt{a^{2}} \sqrt{a^{5}}15a2⋅5a5=53a2a5
If the variableaaa is real, then: 53a2a5=53a5∣a∣5 \sqrt{3} \sqrt{a^{2}} \sqrt{a^{5}} = 5 \sqrt{3} \sqrt{a^{5}} \left|{a}\right|53a2a5=53a5∣a∣