y′′′−6y′′+8y′=0

asked by guest
on Nov 16, 2024 at 6:46 am



You asked:

Solve the equation \(y^{\prime \prime \prime} - 6 \cdot y^{\prime \prime} + 8 \cdot y^{\prime} = 0\) for the variable \(y\).

MathBot Answer:

\[y{\left(t \right)} = C_{2} e^{2 t} + C_{3} e^{4 t} + C_{1}\]

\(C_{1}\), \(C_{2}\), \(C_{3}\) are arbitrary constants.


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).