sin2x -tanx/cos2x =tanx

asked by guest
on Apr 02, 2025 at 12:58 pm



You asked:

Solve the equation sin⁡(2x)−tan⁡(x)cos⁡(2x)=tan⁡(x)\sin\left( 2 x \right) - \frac{\tan\left( x \right)}{\cos\left( 2 x \right)} = \tan\left( x \right) for the variable xx.

MathBot Answer:

The real solutions are: x={2πn  |  n∈Z}≈{6.2831853n  |  n∈Z}x={π(1+2n)  |  n∈Z}≈{6.2831853n+3.1415927  |  n∈Z}\begin{aligned}x &= \left\{2 \pi n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n\; \middle|\; n \in \mathbb{Z}\right\}\\x &= \left\{\pi \left(1 + 2 n\right)\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n + 3.1415927\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}

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