Math Problem Solver

$$\frac{\sqrt{128}}{16} + \sqrt{32} = \frac{9 \sqrt{2}}{2} \approx 6.36396103067892771960759925894364$$

$$\begin{aligned}\frac{\sqrt{128}}{16} + \sqrt{32}&=\sqrt{128} \cdot \frac{1}{16} + \sqrt{32}\\&=8 \cdot \sqrt{2} \cdot \frac{1}{16} + \sqrt{32}\\&=\frac{1}{2} \cdot \sqrt{2} + \sqrt{32}\\&=\frac{1}{2} \cdot \sqrt{2} + 4 \cdot \sqrt{2}\\&=\frac{9}{2} \cdot \sqrt{2}\end{aligned}$$