$\sqrt{128}$ / 16 + $\sqrt{32}$

asked by guest
on Nov 28, 2024 at 9:50 am



You asked:

Evaluate the expression: \(\frac{\sqrt{128}}{16} + \sqrt{32}\)

MathBot Answer:

\[\frac{\sqrt{128}}{16} + \sqrt{32} = \frac{9 \sqrt{2}}{2} \approx 6.36396103067892771960759925894364\]

\[\begin{aligned}\frac{\sqrt{128}}{16} + \sqrt{32}& = \sqrt{128} \cdot \frac{1}{16} + \sqrt{32}\\& = 8 \cdot \sqrt{2} \cdot \frac{1}{16} + \sqrt{32}\\& = \frac{1}{2} \cdot \sqrt{2} + \sqrt{32}\\& = \frac{1}{2} \cdot \sqrt{2} + 4 \cdot \sqrt{2}\\& = \frac{9}{2} \cdot \sqrt{2}\end{aligned}\]

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