n*m*m*n*n*m*m
asked by guest on Apr 02, 2025 at 1:10 pm
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MathBot Answer:
nm⋅mn⋅nm⋅m=m4n3n m \cdot m n \cdot n m \cdot m = m^{4} n^{3}nm⋅mn⋅nm⋅m=m4n3