simplify:
$\frac{x^2-1}{2x^2}$ x $\frac{x}{x+1}$
You asked:
Simplify the expression: \(\frac{{x}^{2} - 1}{2 \cdot {x}^{2}} \cdot x \cdot \frac{x}{x + 1}\)
MathBot Answer:
Simplified:
\[ \frac{{x}^{2} - 1}{2 \cdot {x}^{2}} \cdot x \cdot \frac{x}{x + 1} = \frac{x}{2} - \frac{1}{2} \]
Expanded:
\[ \frac{{x}^{2} - 1}{2 \cdot {x}^{2}} \cdot x \cdot \frac{x}{x + 1} = \frac{x^{4}}{2 x^{3} + 2 x^{2}} - \frac{x^{2}}{2 x^{3} + 2 x^{2}} \]
Factored:
\[ \frac{{x}^{2} - 1}{2 \cdot {x}^{2}} \cdot x \cdot \frac{x}{x + 1} = \frac{x - 1}{2} \]
asked 10 months ago
active 10 months ago