Power[\(40)Divide[1549.73*32,Power[x,2]-16]\(41),2]= Power[2500,2]

asked by guest
on Nov 18, 2024 at 8:31 am



You asked:

Solve the equation (1549.73⋅32x2−16)2=25002{\left( \frac{1549.73 \cdot 32}{{x}^{2} - 16} \right)}^{2} = {2500}^{2} for the variable xx.

MathBot Answer:

The 4 solutions to the equation are: x=−559946125≈−5.9863632x=559946125≈5.9863632x=−59946125i≈−1.9587098ix=59946125i≈1.9587098i\begin{aligned}x &= - \frac{\sqrt{559946}}{125} \approx -5.9863632\\x &= \frac{\sqrt{559946}}{125} \approx 5.9863632\\x &= - \frac{\sqrt{59946}}{125} i \approx -1.9587098 i\\x &= \frac{\sqrt{59946}}{125} i \approx 1.9587098 i\end{aligned}

ii is the imaginary unit, defined as i2=−1i^2 = -1.

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