Power[\(40)Divide[1549.73*32,Power[x,2]-16]\(41),2]= Power[2500,2]
asked by guest
on Nov 18, 2024 at 8:31 am
You asked:
Solve the equation
(x2−161549.73⋅32)2=25002 for the variable
x.
MathBot Answer:
The 4 solutions to the equation are:
xxxx=−125559946≈−5.9863632=125559946≈5.9863632=−12559946i≈−1.9587098i=12559946i≈1.9587098i
i is the imaginary unit, defined as i2=−1.