(y/x sec y - tan y)dx + ( sec y log x - x) dy =0

asked by guest
on Mar 25, 2025 at 10:06 am



You asked:

Investigate the equation: (yxsec⁡(y)−tan⁡(y))⋅dx+(sec⁡(y)log⁡(x)−x)⋅dy=0\left(\frac{y}{x \sec\left( y \right)} - \tan\left( y \right)\right) \cdot d x + \left(\sec\left( y \right) \log\left( x \right) - x\right) \cdot d y = 0.

+ Submit Question