10=80e^-0.5x

asked by guest
on Nov 17, 2024 at 8:48 am



You asked:

Investigate the equation: \(10 = 80 \cdot {e}^{-0.5} \cdot x\).

MathBot Answer:

The solution is: \[x = \frac{e^{\frac{1}{2}}}{8} \approx 0.20609016\]


\[\begin{aligned}10 &= x \frac{80}{e^{0.5}}\\x \left(- \frac{80}{e^{0.5}}\right) &= -10\\x &= \frac{e^{0.5}}{8}\end{aligned}\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).