solve\:for\:a,\:y=a\left(x-0.3\right)^2+2.1

asked by guest
on Oct 20, 2024 at 6:11 pm



MathBot Answer:

$$\begin{aligned}a &= \frac{\sqrt{100 y - 210}}{10 x - 3}\\a &= - \frac{\sqrt{100 y - 210}}{10 x - 3}\end{aligned}$$

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