5b-48=3b+100

asked by guest
on Apr 06, 2025 at 12:03 pm



You asked:

Solve the equation 5b−48=3b+1005 b - 48 = 3 b + 100 for the variable bb.

MathBot Answer:

The solution is: b=74b = 74

5b−48=3b+1002b=148b=74\begin{aligned}5 b - 48 &= 3 b + 100\\2 b &= 148\\b &= 74\end{aligned}

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