t^(2)-8t+16

asked by guest
on Jan 13, 2025 at 8:54 am



You asked:

Evaluate the expression: \({t}^{2} - 8 t + 16\)

MathBot Answer:

Evaluated



\(\displaystyle {t}^{2} - 8 t + 16 = t^{2} - 8 t + 16 \)


Factored

\[{t}^{2} - 8 t + 16 = \left(t - 4\right)^{2}\]