7/5 as a mixed number
asked by guest on Mar 28, 2025 at 10:39 am
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MathBot Answer:
1251\frac{2}{5}1527÷5=17 \div 5 = 17÷5=1 with remainder 222, so75=1×5+25=1×55+25=1+25=125\tfrac{7}{5} = \tfrac{1 \times 5 + 2}{5} = \tfrac{1 \times 5}{5} + \tfrac{2}{5} = 1 + \tfrac{2}{5} = 1\frac{2}{5}57=51×5+2=51×5+52=1+52=152