Math Problem Solver

\[ \frac{6}{11} + \frac{2}{3} = \frac{40}{33} = 1.\overline{21} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{11}\) and \(\frac{2}{3}\) is \(33\). \[ \begin{aligned} \frac{6}{11} + \frac{2}{3} &= \frac{6 \cdot 3}{11 \cdot 3} + \frac{2 \cdot 11}{3 \cdot 11} \\ &= \frac{18 + 22}{33} \\ &= \frac{40}{33} \end{aligned} \]