(7^x)^2-6.7^X +5=0 Z=7^X

Z^2-6Z+5= 0

Z1=5 y Z2=1

7^X=5 How do i proceed?

asked by guest
on Nov 24, 2024 at 4:25 pm



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


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