d^2-16d+60
asked by guest on Mar 20, 2025 at 6:05 pm
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MathBot Answer:
d2−16d+60=d2−16d+60\displaystyle {d}^{2} - 16 d + 60 = d^{2} - 16 d + 60 d2−16d+60=d2−16d+60
d2−16d+60=(d−10)(d−6){d}^{2} - 16 d + 60 = \left(d - 10\right) \left(d - 6\right)d2−16d+60=(d−10)(d−6)
