\left(\frac{1-tanθ}{\left(1+tanθ\right)}\right)\:\:=\left(\frac{cotθ-1}{cotθ+1}\right)
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\left(\frac{1-tanθ}{\left(1+tanθ\right)}\right)\:\:=\left(\frac{cotθ-1}{cotθ+1}\right)
MathBot Answer:
MathBot is working on a solution to your problem.