6x^2 − x −12/3x^2 − 5x −12
asked by guest on Apr 04, 2025 at 9:47 pm
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6x2−x−123x2−5x−12=6x2−6x−12−4x2\displaystyle 6 {x}^{2} - x - \frac{12}{3 {x}^{2}} - 5 x - 12 = 6 x^{2} - 6 x - 12 - \frac{4}{x^{2}} 6x2−x−3x212−5x−12=6x2−6x−12−x24
6x2−x−123x2−5x−12=2⋅(3x4−3x3−6x2−2)x26 {x}^{2} - x - \frac{12}{3 {x}^{2}} - 5 x - 12 = \frac{2 \cdot \left(3 x^{4} - 3 x^{3} - 6 x^{2} - 2\right)}{x^{2}}6x2−x−3x212−5x−12=x22⋅(3x4−3x3−6x2−2)