(-4-m)^2-4(1)
asked by guest on Apr 07, 2025 at 9:03 am
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MathBot Answer:
(−4−m)2−4⋅1=(−m−4)2−4\displaystyle {\left( -4 - m \right)}^{2} - 4 \cdot 1 = \left(- m - 4\right)^{2} - 4 (−4−m)2−4⋅1=(−m−4)2−4
(−4−m)2−4⋅1=m2+8m+12{\left( -4 - m \right)}^{2} - 4 \cdot 1 = m^{2} + 8 m + 12(−4−m)2−4⋅1=m2+8m+12
(−4−m)2−4⋅1=(m+2)(m+6){\left( -4 - m \right)}^{2} - 4 \cdot 1 = \left(m + 2\right) \left(m + 6\right)(−4−m)2−4⋅1=(m+2)(m+6)