5(3x+1)-2(x-2)
asked by guest on Apr 01, 2025 at 9:52 am
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MathBot Answer:
5(3x+1)−2(x−2)=13x+9\displaystyle 5 \left(3 x + 1\right) - 2 \left(x - 2\right) = 13 x + 9 5(3x+1)−2(x−2)=13x+9
5(3x+1)−2(x−2)=13x+95 \left(3 x + 1\right) - 2 \left(x - 2\right) = 13 x + 95(3x+1)−2(x−2)=13x+9