h(x) = \begin{cases}

\dfrac{1}{x-5} & , & x = 0 \\\\

-(x-4)^2& , & x = 7\\\\

3x-2& , & x \neq 0,7\end{cases}

asked by guest
on Jan 15, 2025 at 9:42 pm



Mathbot Says...

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