d^2+2d-48
asked by guest on Mar 20, 2025 at 6:03 pm
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MathBot Answer:
d2+2d−48=d2+2d−48\displaystyle {d}^{2} + 2 d - 48 = d^{2} + 2 d - 48 d2+2d−48=d2+2d−48
d2+2d−48=(d−6)(d+8){d}^{2} + 2 d - 48 = \left(d - 6\right) \left(d + 8\right)d2+2d−48=(d−6)(d+8)