exp(ln(ln(x))*y)
You asked:
Evaluate the expression: \({e}^{\ln\left( \ln\left( x \right) \right) \cdot y}\)
MathBot Answer:
\[{e}^{\ln\left( \ln\left( x \right) \right) \cdot y} = e^{y \log{\left(\log{\left(x \right)} \right)}}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).