600-200Q+350Q²+30Q³ given Q= 20

asked by guest
on Nov 30, 2024 at 12:36 am



You asked:

Calculate the value of 600−200Q+350Q2+30Q3600 - 200 Q + 350 {Q}^{2} + 30 {Q}^{3} when Q=20Q = 20.

MathBot Answer:

600−200Q+350Q2+30Q3=376600600 - 200 Q + 350 {Q}^{2} + 30 {Q}^{3} = 376600

30Q3+350Q2−200Q+600=30⋅203+350⋅202+600−200⋅20=600−200⋅20+350⋅400+30⋅400⋅20=600−200⋅20+30⋅400⋅20+140000=600+30⋅400⋅20−4000+140000=600−4000+140000+240000=376600\begin{aligned}30 Q^{3} + 350 Q^{2} - 200 Q + 600&=30 \cdot 20^{3} + 350 \cdot 20^{2} + 600 - 200 \cdot 20\\&=600 - 200 \cdot 20 + 350 \cdot 400 + 30 \cdot 400 \cdot 20\\&=600 - 200 \cdot 20 + 30 \cdot 400 \cdot 20 + 140000\\&=600 + 30 \cdot 400 \cdot 20 -4000 + 140000\\&=600 -4000 + 140000 + 240000\\&=376600\end{aligned}


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