solve y''+3y'+2y=12 exp(x)
You asked:
Investigate the equation: \(y^{\prime \prime} + 3 \cdot y^{\prime} + 2 y = 12 {e}^{x}\).
MathBot Answer:
\[y{\left(x \right)} = 2 e^{x} + C_{1} e^{- 2 x} + C_{2} e^{- x}\]
\(C_{1}\), \(C_{2}\) are arbitrary constants.
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).