((4.61*10^-3)*X)^2+(4.61*10^-3)*X*(349.15+1361.17)+(349.15^2+1361.17^2-3500^2-349.15*1361.17)

asked by guest
on Nov 17, 2024 at 7:24 am



You asked:

Evaluate the expression: \({\left( 4.61 \cdot {10}^{-3} \cdot X \right)}^{2} + 4.61 \cdot {10}^{-3} \cdot X \cdot \left(349.15 + 1361.17\right) + {349.15}^{2} + {1361.17}^{2} - {3500}^{2} - 349.15 \cdot 1361.17\)

MathBot Answer:

Evaluated



\(\displaystyle {\left( 4.61 \cdot {10}^{-3} \cdot X \right)}^{2} + 4.61 \cdot {10}^{-3} \cdot X \cdot \left(349.15 + 1361.17\right) + {349.15}^{2} + {1361.17}^{2} - {3500}^{2} - 349.15 \cdot 1361.17 = \frac{212521 X^{2}}{10000000000} + \frac{9855719 X}{1250000} - \frac{107505630141}{10000} \)

Expanded

\[{\left( 4.61 \cdot {10}^{-3} \cdot X \right)}^{2} + 4.61 \cdot {10}^{-3} \cdot X \cdot \left(349.15 + 1361.17\right) + {349.15}^{2} + {1361.17}^{2} - {3500}^{2} - 349.15 \cdot 1361.17 = \frac{212521 X^{2}}{10000000000} + \frac{9855719 X}{1250000} - \frac{107505630141}{10000}\]

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