∫0axsin((3∗22/7)x/a)sin(22x/7a)dx
asked by guest
on Mar 13, 2025 at 11:45 am
You asked:
Evaluate the integral:
∫0axsin(a73⋅22x)sin(7a22x)dx
MathBot Answer:
∫0axsin(a73⋅22x)sin(7a22x)dx=−15488147a2−17621a2sin(722)cos(766)+15488245a2sin(722)sin(766)+1767a2sin(766)cos(722)+15488147a2cos(722)cos(766)