Math Problem Solver

\[ \frac{1}{15} + \frac{1}{40} = \frac{11}{120} = 0.091\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{15}\) and \(\frac{1}{40}\) is \(120\). \[ \begin{aligned} \frac{1}{15} + \frac{1}{40} &= \frac{1 \cdot 8}{15 \cdot 8} + \frac{1 \cdot 3}{40 \cdot 3} \\ &= \frac{8 + 3}{120} \\ &= \frac{11}{120} \end{aligned} \]